核心∑k=1n[F(k)−F(k−1)]=F(n)−F(0)\sum_{k=1}^{n} \bigl[ F(k) - F(k-1) \bigr] = F(n) - F(0)k=1∑n[F(k)−F(k−1)]=F(n)−F(0)
即相邻项相减后,中间项全部抵消,只剩首尾
基础:(n+1−n)(n+1+n)=1(\sqrt{n+1} - \sqrt{n})(\sqrt{n+1} + \sqrt{n}) = 1(n+1−n)(n+1+n)=1,从而
常数倍:1n+n+k=1k(n+k−n)\displaystyle \frac{1}{\sqrt{n} + \sqrt{n+k}} = \frac{1}{k}\left(\sqrt{n+k} - \sqrt{n}\right)n+n+k1=k1(n+k−n)。